Re: Submitting a Form

From: Date: Tue, 17 Dec 2002 17:44:54 +0000
Subject: Re: Submitting a Form
References: 1  Groups: php.general 
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1. Try: $_POST[Test] 2. $_POST[testmultiple][2] (Will give you position 3 of the select.) Or: $list = implode($_POST[testmultiple]); Will give you the values selected in $list in a comma seperated list. 3. print_r($_REQUEST) On Tue, 2002-12-17 at 12:38, Jay Thayer wrote: I have a php page, with a form I am attempting to submit. <form method="Post" action="submitTest.php"> <input type="hidden" name="Test" value="Test Value"> <input type="submit" value="Submit" name="SubmitTest"> <form> In submitTest.php, I simply put <?php print $Test; ?> Yet, I continually get the browser message: "Notice: Undefined variable: Test in ...\submittest.php on Line 2 1. Any reason that I can not pass the variable to the submit page? I am using an Apache Web Server on Windows XP. I am simplying attempting to pass a variable from one page to another, so I can update my database. This is just a simple test that is failing. 2. If I have a <select name="testmultiple" multiple> HTML tag, how can I reference the x# of variables that are selected in that form value in the submittest page? I would want to get every option that is selected in the page. 3. Is there a variable so that I can see everything that is passed from the form, some debug variable I could "print()" to see everything that was passed from the form? Anyone have an idea? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Adam Voigt (adam@cryptocomm.com) The Cryptocomm Group My GPG Key: http://64.238.252.49:8080/adam_at_cryptocomm.asc

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