Re: nested if in a for statement

I think your error is this: $userVars = array($nameFirst, $nameLast, $pass, $pass2, $auth, $dob_year, $dob_month, $dob_day); for ($i=0; $i <= count($userVars); $i++) { if (empty($userVars[$i])) { echo "please enter all required info"; break; } } You're using eight variables, so $userVars have indexes like these $userVars[0]=$nameFirst, $userVars[1]=$nameLast, ... , $userVars[7]=$dob_day In the for loop you're using $i <= count($userVars), that is $i<=8, but you declare $i =0... so the loop is running nine times 0,1,...,8 The echo that you're seeing is the last run, cause empty($userVar[8]) is true (there is nothing in that index) Got it? Make it $i < count($userVars). I hope this help you. Douglas. __________________________________________________ Do you Yahoo!? Yahoo! Mail Plus - Powerful. Affordable. Sign up now. http://mailplus.yahoo.com