Re: Undefined Functions

Try defining them at the top instead... Beauford.2002 wrote:

Then based on the one below that doesn't work, what is the problem with it? As I said, the functions are at the bottom of the script. The only thing after them is the closing ?>. I also said that they work if I don't call them from within an if/else. This tells me it is not where it is defined but where it is being called from. Your saying this doesn't matter, but have not given any reasons for my problems. If you could elaborate on this it would be appreciated. Beauford ----- Original Message ----- From: "Rasmus Lerdorf" <rasmus@php.net> To: "Beauford.2002" <beauford.2002@rogers.com> Cc: "PHP General" <php-general@lists.php.net> Sent: Monday, December 23, 2002 11:14 AM Subject: Re: [PHP] Undefined Functions

Like I said, where you define your function is important, not where you call it. If you are defining and calling it all in the same place, then yes, obviously it makes a difference. -Rasmus On Mon, 23 Dec 2002, Beauford.2002 wrote:

I have a function at the bottom of my script which is called from

withing an

if/else statement. If I take it out of the if/else and just call the function it works fine (except I don't get the results I want). So it appears where you are calling it from does matter. See the examples

below.

This isn't the first time either, I have had to redo several scripts for this project because of it. If I'm doing this wrong based on the

examples

below, please let me know. Thanks. i.e.

This doesn't work.                                            This does.

some code ......                                                 some
     

code

......... If ($bob) { gotofunction($bob); }

gotofunction($bob);

elseif ($sally) { gotonextfunction($sally); } gotonextfunction($sally)

      else { gotolastfunction(); }

gotolastfunction()

some other code .....                                         some other

code

function gotofunction($bob)                               function

gotofunction($bob)

function gotonextfunction()                                 function

gotonextfunction()

function gotolastfunction()                                  function

gotolastfunction() ----- Original Message ----- From: "Rasmus Lerdorf" <rasmus@php.net> To: "Beauford.2002" <beauford.2002@rogers.com> Cc: "PHP General" <php-general@lists.php.net> Sent: Sunday, December 22, 2002 11:16 PM Subject: Re: [PHP] Undefined Functions

An undefined function error has nothing to do with where you are

calling

the function from. It has to do with whether or not you have defined

the

function you are calling. -Rasmus On Sun, 22 Dec 2002, Beauford.2002 wrote:

Hi, I previously asked a question about getting undefined function

errors in

my

script and someone mentioned that it may be that I am calling it

from

within

an if or else statement. This turned out to be the case. Now the

question -

is there a way around this? What I need to do resolves around many

different

conditions, and depending on the what's what I call the necessary

function.

I have looked my script over and over and can not see any other way

of

doing

this. I am fairly new to PHP and maybe there is a better way, and

I'm

open

to suggestions. TIA Example: if ($a == $b) call function one; elseif ($a > $b) call function two; elseif ($a == $c) call function two; elseif ($a < $b) call function two; elseif ($c > $b) call function two; elseif ($d == $e) call function two; -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

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