Re: parse error

From: Date: Sat, 04 Jan 2003 01:04:00 +0000
Subject: Re: parse error
References: 1  Groups: php.general 
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In addition to the other errors pointed out... I assume you want a loop. change while($row = mysql_fetch_array($response)); to while($row = mysql_fetch_array($response)) { Take care, Greg -- phpDocumentor http://www.phpdoc.org > while($row = mysql_fetch_array($response)); > > > echo("<p align="center"><img border="0" src="images/banner_chico_bio.jpg" > width="274" height="43"></p>"); > print "<img src=\" " . $row["banner_nombre"] . > "\">"; > echo("<div align="center">"); > echo("<center>"); > echo("<table border="1" width="500" > height="25">"); > echo("<tr>"); > echo("<td width="500" height="25">"); > echo("<div align="left">"); > echo("<table border="0" width="125" > height="27">"); > echo("<tr>"); > echo("<td width="125" height="27"></td>"); > echo("</tr>"); > echo("</table>"); > echo("</div>"); > echo("<p>"); > > print($row["texto"] ."<br>\n"); > > echo("</td>"); > echo("</tr>"); > echo("</table>"); > echo("</center>"); > echo("</div>"); > } > > ?> > > > </div> > > </html> > >

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