RE: [PHP] Sorry, PHP & HTML

Your print line needs to have the quotes escaped. Unless print works different than echo the line should read... print "<a href=\http://www.hotmail.com\><img src=\"logos/constr12.gif\" width=\"100\" height=\"100\" border=\"0\"></a>"; Larry S. Brown Dimension Networks, Inc. (727) 723-8388 -----Original Message----- From: Denis L. Menezes [mailto:menezesd@singnet.com.sg] Sent: Saturday, January 11, 2003 8:32 PM To: PHP general list Subject: [PHP] Sorry, PHP & HTML Hello friends. I have a database from which I take 2 variables as follows : $CompanyWebsite $CompanyLogo I want to dynamically show two GIFs and when the user clicks on these, they should go to http://www.hotmail.com and http://www.yahoo.com respectively. I have problem only with the displaying(the error is parse error on the lines containing <a> tags), for which I use the folowing code. Please tell me where I am wrong. <?php Print " Organisation address : ".$row[CompanyAddress]." <br>\n".""; Print " Organisation website : ".$row[CompanyWebsite]."<br>\n"." "; // I am displaying this when testing only. Print " Organisation logo : ".$row[CompanyLogo]."<br>\n"." ";?> // I am displaying this when testing only. Print "<a href="http://www.hotmail.com"><img src="logos/constr12.gif" width="100" height="100" border="0"></a>"; Print "<a href="http://www.yahoo.com"><img src="logos/constr12.gif" width="100" height="100" border="0"></a>"; ?> Thanks Denis