Re: Regular Expression Help in my PHP! Sorry if wrong group

> I have a script that turns certain words into links. That I am having > no problems with, it is when I want to turn the links back in to plain > text that I am having the problem. Below are my examples. And I know > my regex is being greedy but I don't know how to stop it from being so > damn greedy I thought the ? mark would help but it didn't. Any help > would be appreciated. So here it goes: > > > The code: > > $strStr = "This is <a href=test>USF</a> at <a href=test>Tampa</a>. > This > is <a href=test>USF</a> at <a href=test>Tampa</a>."; > echo $strStr."<br>\n"; > $strStr = preg_replace("/<a.*?>(Tampa)<\/a>/","\\1",$strStr); > echo $strStr."<br>\n"; > $strStr = preg_replace("/<a.*?>(USF)<\/a>/","\\1",$strStr); > echo $strStr."<br>\n"; > > The output: > > This is <a href=test>USF</a> at <a href=test>Tampa</a>. This is <a > href=test>USF</a> at <a href=test>Tampa</a>. > This is Tampa. This is Tampa. > This is Tampa. This is Tampa. > > The expected output: > > This is <a href=test>USF</a> at <a href=test>Tampa</a>. This is <a > href=test>USF</a> at <a href=test>Tampa</a>. > This is <a href=test>USF</a> at Tampa. This is <a href=test>USF</a> at > Tampa. > This is USF at Tampa. This is USF at Tampa. Well, a /U at the end of your pattern will make it so the regex isn't greedy. That may solve your problem. Or you could try matching "/<a[^>]+>(Tampa)<\/a>/" which will match an <a followed by anything that's not a >, followed by a >. So it essentially makes it ungreedy. ---John Holmes...