Re: Fw: [PHP] $header = "Location:........" being ignored!

give some output in the if-construct to see if it even matches. I believe there is some problem with the variables used in there, the location should work though. On Tue, 21 Jan 2003 06:09:01 -0600 remery@emeryloftus.com (Rick Emery) wrote: > if ( $_POST['passwd'] != $db['password'] ) > { header("Location: loginfailed.html"); exit; > } > ----- Original Message ----- > From: "Shams" <shamskhanmalik@hotmail.com> > To: <> > Sent: Tuesday, January 21, 2003 3:48 AM > Subject: [PHP] $header = "Location:........" being ignored! > > > Hi Group, > > I basically have some simple code such as: > > ================================================== > > if ( $_POST['passwd'] != $db['password'] > { header("Location: loginfailed.html"); > } > > //else > > $header = "Location: success.html"; > > ================================================== > > however, when I run this code, using a <FORM> to submit password, username, > etc...... if the passwords do not match, the page is forwarded to > success.html ! > > Is there anything obvious that I am doing wrong? > > Thanks, > Shams > > p.s. I don't want to use else{} because I have lots of if() checks! > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > > -- Thomas Seifert mailto:thomas.seifert@myphorum.de http://www.MyPhorum.de