Re: date calculation

Dear Stephen, Good clue!! Is it working allways without problem such as 29 feb? And one more hel how can I write "1 2 2003" instead of "1 february 2003" I wrote but directly but doesn' t work thanks "Stephen Willcock" <stephen.willcock@virgin.net> wrote in message news:20030216140648.58868.qmail@pb1.pair.com... > Try: > > $today = strtotime ("1 february 2003"); > $enddate = strtotime ("2 february 2003"); > $diff = $enddate - $today; > > Should give you a clue! > > SW > > > "Qt" <web_tur@yahoo.com> wrote in message > news:20030216134414.47538.qmail@pb1.pair.com... > > Dear Kevin, > > > > I used timestamp allready as following; > > > > $today = strtotime ("1 february 2003"); > > $enddate = strtotime ("1 march 2003"); > > > > $diff = $enddate - $today; > > > > But result comes as > > > > 2419200 > > > > How can I convert that numbers to days > > > > Best Regards > > > > > > > > "Kevin Waterson" <kevin@oceania.net> wrote in message > > news:20030216234336.21fbdb98.kevin@oceania.net... > > > This one time, at band camp, > > > "qt" <web_tur@yahoo.com> wrote: > > > > > > > Dear Sirs, > > > > > > > > How can I add or subtract two date easily. Is therea any lib or > function > > > > about this. I can not find any easy way in the manual > > > > > > if the dates are timestamps, simply > > > > > > $new = $timestamp2 - $timestamp1; > > > > > > cheers > > > Kevin > > > > > > -- > > > ______ > > > (_____ \ > > > _____) ) ____ ____ ____ ____ > > > | ____/ / _ ) / _ | / ___) / _ ) > > > | | ( (/ / ( ( | |( (___ ( (/ / > > > |_| \____) \_||_| \____) \____) > > > Kevin Waterson > > > Port Macquarie, Australia > > > > > >