RE: [PHP] dummy variable

> I have some text that outputs to a page without a variable, example: echo > "text"; > > the echo has text that I would like to preg_replace. > > since there is no variable, is it possible to make a $dummy variable so > either way it replaces the text that i would like inside the echo? > > this is the function that I'd like to use: > > preg_replace("/\[url=(.*?)\](.*?)\[\/url\]/si", "<a href=\\1 > target=_blank>\\2</a>"); > > How do I do this? Use output buffering. Start the buffer before the echos, capture the output, do the preg_replace, and display the result. More info on the manual page. http://www.php.net/manual/en/ref.outcontrol.php ---John W. Holmes... PHP Architect - A monthly magazine for PHP Professionals. Get your copy today. http://www.phparch.com/