Re: Auto Incrementing a Variable name?
| From: | Jason k Larson | Date: | Tue, 25 Feb 2003 21:37:16 +0000 |
| Subject: | Re: Auto Incrementing a Variable name? | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-137145@lists.php.net to get a copy of this message | ||
$name1 = 'Hello, World!';
$i = 1;
$var = 'name'.$i;
print ${$var};
HTH,
Jason k Larson
Jeff Pauls wrote:
Hi, I've been playing with this for a while now. Say I had the following variables: $name1 = "joe"; $name2 = "janis"; $name3 = "joanne"; Is there a way in php to increment the variable name not the value? Something like this.... for ($i = 1; $i <= 3; $i++) {$arr_name[$i] = $name.$i; // I want $name1,$name2,$name3 etc.... }This way say if I had 500 database queries that need to be updated I could just loop through each and just change the record id..... for ($i = 1; $i <= 500; $i++) { $query_update = "UPDATE table SET name=' $arr_name[$i]', WHERE person_id='$i"; $result_update = mysql_query($query_update) or die("Query failed"); } instead of doing something like this: $query_update1 = "UPDATE table SET name=' $name1', WHERE person_id='1"; $result_update1 = mysql_query($query_update1) or die("Query failed"); $query_update2 = "UPDATE table SET name=' $name2', WHERE person_id='2"; $result_update2 = mysql_query($query_update2) or die("Query failed"); $query_update3 = "UPDATE table SET name=' $name3', WHERE person_id='3"; $result_update3 = mysql_query($query_update3) or die("Query failed"); etc..... Anybody? There has to be a way of doing this... Thanks, Jeff