Re: How do I display the script file name?

Actually, echo can handle multiple arguments, which it thinks those are. echo 'foo', "bar", $foobar; //one example //echo x3 echo 'foo'; echo "bar"; echo $foobar; echo 'foo'."bar".$foobar; //yet another echo example There are even more complex ways too and, of course, the use of ()s ... but I think I've made my point. HTH, Jason k Larson M.A.Bond wrote:

With the output you are getting you will not see the output from the .' '. As it inserts a space into the ouputted text. There is an error after the $_SERVER['PHP_SELF'] the , should be a . (is this just a typo in the e-mail?) Thanks Mark -----Original Message----- From: Stephen Ford [mailto:stephen_ford@ntlworld.com] Sent: 27 February 2003 16:47 To: php-general@lists.php.net Subject: Re: [PHP] How do I display the script file name? Partial success. The code and output are shown below. There are no errors. What does the ".' '." do pls. Have tried a variety of combinations to see the effect. Nothing to see... :-( ===PHP============== <?php echo "<P>Line #1 ".' '.$_SERVER['PHP_SELF'], "</P>"; echo "<P>Line #2</P>"; echo "<P>Line #3</P>"; echo "<P>Line #4 ".' '.$_SERVER['SCRIPT_NAME'].' '.

     $_SERVER['SCRIPT_FILENAME'].' '.
     $_SERVER['PHP_SELF']."</P>";

echo "<P>Line #5</P>"; echo "<P>Line #6 ", __FILE__,"</P>"; ?> ===IE6 display=============== Line #1 Line #2 Line #3 Line #4 Line #5 Line #6 <Pathname removed for security> ================== Stephen