Re: Populate var with function output string?

You da man, Leif. That did the trick. Didn't try the output buffering idea. I need to look into that area. Thanks for illuminating things a bit............ --Noah ----- Original Message ----- From: "Leif K-Brooks" <eurleif@buyer-brokerage.com> To: "CF High" <noah@newminddesign.com> Cc: <php-general@lists.php.net> Sent: Monday, March 03, 2003 5:01 PM Subject: Re: [PHP] Populate var with function output string? > Try adding each output string to a variable, then returning it, like: > > function return_string(count) { > $return = ''; > for ($x = 0; $x < $count; $x++) { > > $return.= "<option value=$x> Row $x</option>"; > > } > return $return; > > } > > If you can't do that for some reason, try using output buffering. > www.php.net/ob-start > > CF High wrote: > > >Hey all. > > > >Is it possible to populate a var with an output string generated by a > >function? So: > > > >******************************* > >function write_string(count) { > > > > for ($x = 0; $x < $count; $x++) { > > > > echo "<option value=$x> Row $x</option>"; > > > > } > > > >} > > > >$my_string = write_string(5); > > > >echo $my_string; > >******************************* > > > >I need $count option elements stored in $my_string. How to make this happen. > > > >Thanks for any ideas, > > > >--Noah > > > > > >-- > > > > > > > > > > > > > > -- > The above message is encrypted with double rot13 encoding. Any unauthorized attempt to decrypt it will be prosecuted to the full extent of the law. > > >