AW: [PHP] Re: How to use the fields of an array as individual parameter for a function

Sure. But how do i return the array elements of $params as individual parameters from processArray? Any code? Would be great. --- CB -----Ursprüngliche Nachricht----- Von: Patrick Schnegg [mailto:info@killersushi.ch] Gesendet: Dienstag, 4. März 2003 11:40 An: php-general@lists.php.net Betreff: Re: [PHP] Re: How to use the fields of an array as individual parameter for a function In this case, I would write a third function that processes the array for passing it correctly to foo2. In a way that you will end up with something like this: $object = new foo2(processArray($params)); Have you thought about that? "Christian Bartels" <mailinglisten@thebartels.de> wrote in message news:000901c2e238$aea7be70$0300a8c0@cblaptop... Yes, i thought about this already. But it is more work for me to do, 'cause i would have to rewrite the constructors of several classes. Anyways i am interested, whether this (pass the elements as variables) is possible in php. --- CB -----Ursprüngliche Nachricht----- Von: Patrick Schnegg [mailto:info@killersushi.ch] Gesendet: Dienstag, 4. März 2003 11:11 An: php-general@lists.php.net Betreff: [PHP] Re: How to use the fields of an array as individual parameter for a function Hi Instead of worrying how to pass the individual parameters to foo2, simply pass the whole array to it and process it within the function itself. Seems more logical to me. "Christian Bartels" <mailinglisten@thebartels.de> wrote in message news:000201c2e233$c3ea0ae0$0300a8c0@cblaptop... Hello! I'm new here on the list. I hope you can help me! :) I have a function foo1 which has a parameter $params. In the function i want to pass $params to another function foo2. if $params is an array the elements should be passed to foo2 as individual parameters. Is this possible? How do i do that? Example: function foo1($params) { if (is_array($params)) { $object = new foo2(GET THE ELEMENTS OF $params AS INDIVIDUAL PARAMETERS HERE); } else { $object = new foo2($params); } } So when this is called: foo1(array('blue', 'red', 'green')); In foo1 foo2 should be called like this: foo2('blue', 'red', 'green'); Is this possible? Thanks for any help! (sorry about my english ;-)) --- CB -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php