Re: fopen

that example code is trying to print out data which refers to the integer filehandle of the fopen. To get data out of the file that you have opened, you will need to read() it in. John Taylor-Johnston wrote:

#http://www.php.net/manual/en/function.fopen.php $contents = fopen ("/home/pathto/file.txt", "r"); if ($contents){echo"<textarea>$contents</textarea>";} else{echo "no contents there";} Questions: What is the use of "@fopen"? Does anyone see a better way?