Re: fopen and PHP 4.3.x
| From: | Liam Gibbs | Date: | Tue, 11 Mar 2003 03:42:40 +0000 |
| Subject: | Re: fopen and PHP 4.3.x | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-139077@lists.php.net to get a copy of this message | ||
> This is the code around line 30.....
> $local_file = $feed;
> $fp = fopen($local_file, "r");
>
> Anyone have any ideas? I have looked over the manual and the only thing I
> could find similar to this is in the comments. Apache was restarted.
I get the same thing so I'm working through it. But here are some ideas that
may work for you: What are the permissions of the file in question? And do
you know the exact path of the file? Also, is the first line above (line
29?) needed? Why not just use $feed as the filename?