RE: [PHP] Subtracting two dates

Is there a way not to round the number but get a whole number? I don't want to have 1.5 days show as 2 days because it really has not gone into day 2? -----Original Message----- From: Justin French [mailto:justin@indent.com.au] Sent: Monday, March 10, 2003 8:27 PM To: Ben C.; php-general@lists.php.net Subject: Re: [PHP] Subtracting two dates <? $otherDate = "2003-11-15"; // yyyy-mm-dd format $otherDateStamp = strtotime($otherDate); // now a unix timestamp $difference = time() - $otherDateStamp; // diff in seconds ?> Then you need to decide if you want to show days, or hours, or years difference... I'll show you hours and days: <? $differenceHours = $difference / 3600; // 60secs x 60 mins $differenceDays = $difference / 86400; // 60 x 60 x 24 hours ?> You then need to round the number using round(). Justin on 11/03/03 3:02 PM, Ben C. (benc@cox.net) wrote: > There are a lot of artlicles on this but I need a simple solution. I need > to subtract two dates as follows: > > $date = date("Y-m-d"); > $date1 = "2003-03-03"; > $differencedate = ($date - $date1); > echo $differencedate; > > When I do this I get 0. Please help! > > > -------------------------------------------------------------------------- > The content of this email message and any attachments are confidential and > may be legally privileged, intended solely for the addressee. If you are > not the intended recipient, be advised that any use, dissemination, > distribution, or copying of this e-mail is strictly prohibited. If you > receive this message in error, please notify the sender immediately by reply > email and destroy the message and its attachments. >