Re: Search/Regular Expression problem

If you're splitting them up with preg_split(), you can combine them with implode(). Something like $foo = ".*" . implode(".*", $words); Or don't use an array at all. Just replace anything that's not a valid search character... $regex = preg_replace("/[^A-Za-z]/", ".*", $search); J Kelvin Poon wrote: > Hi, > > I am sorry if this problem is too easy but I just can't figure out a way > to do this. > > I am making a search engine and I would have the user to type a sentence > to search for. > > Let's say it is stored in $search. > > My search enginue will bring up a result IF and only if ALL of the words > in > $search exist in the result. For example > if > > $search = Vax Useful Commands > > Then the result is only true if (eregi(".*Vax.*Useful.*Commands.*", > 'possible result')) is true > > Now, I don't know how many words there are in $search initially. How do I > do a search like that? I mean if I know $search is 3 words then I can do > > $words = preg_split("/ /", $search); > > if (eregi(".*words[0].*words[1].*words[2].*", 'possible result')) { > ..... > } > > > Even if I know how many words there are, everytime the number of words in > $search can be different. > > Can anybody give me any ideas? > Thanks a lot > > Kelvin