RE: [PHP] mySQL query - command "LIKE" OR "="

= does not take the wildcard (%). -----Original Message----- From: Harry.de [mailto:harald.mohring@gmx.de] Sent: Friday, March 28, 2003 2:38 PM To: php-general@lists.php.net Subject: [PHP] mySQL query - command "LIKE" OR "=" Hi, i want to make a mySQL query where the result should be in $result1 any sting with a phrase of $search in $result2 any sting with the exact phrase of $search $result1 works fine, but $result2 gives out an empty sting $result1 = mysql_query("SELECT name FROM table WHERE name LIKE '%".strtolower($search)."% "); $result2 = mysql_query("SELECT name FROM table WHERE name = '%".strtolower($search)."% "); e.g. row 1 in name = "my big appletree in the garden" row 2 in name = "my big apple in the garden" so the result should be in $result2 with $search="apple" 2 Can anybody help me Harry -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php