Re: Ereg question

This is what I get when I echo $formsave["dob"] - 9/09/199. It was inputted as 09/09/1990. B. ----- Original Message ----- From: "John W. Holmes" <holmes072000@charter.net> To: "'Beauford'" <beauford.2002@rogers.com>; "'PHP General'" <php-general@lists.php.net> Sent: Sunday, March 30, 2003 2:28 PM Subject: RE: [PHP] Ereg question > > I am using ereg to validate the format of a date entry (mm/dd/yy), but > if > > the year ends in a 0, it is being stripped and as such produces an > error. > > So > > 1990 would be 199. The dob is being inputted by a form.... > > > > Here is my code: > > > > if (!ereg("^([0-9]{2})/([0-9]{2})/([0-9]{4})$", $formsave["dob"], > $parts)) > > { > > $error["dob"] = "*"; $message["dob"] = "Invalid date > > format!"; > > $dob = " \"$parts[3]-$parts[2]-$parts[1]\""; > > } > > So is $formsave['dob'] being changed before you get to this code, > causing the check to fail? What else are you doing with > $formsave['dob']? Nothing here is going to cause it to drop a zero from > the end. > > Your code doesn't make much sense, though. If the ereg() fails, $parts > is not going to have any value, so why are you referencing $part[1], > $part[2], etc... ? > > ---John W. Holmes... > > PHP Architect - A monthly magazine for PHP Professionals. Get your copy > today. http://www.phparch.com/ > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >