Re: Submit Image Button

ok, sorry I'm a newb...what do I do with that info? I saw that page, but it makes no sense to me Thomas "John Coggeshall" <john@coggeshall.org> wrote in message news:000301c2f989$dd4d1f50$1f01a8c0@cooglewin... > > http://www.php.net/manual/en/language.variables.external.php > > <input type="image" src="image.gif" name="sub"> > > This creates variables $_GET['sub_x'] and $_GET['sub_y'] containing the > X/Y cordinate where the button was clicked (assuming it was GET method > form submission) > > John > > -~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~- > John Coggeshall > john at coggeshall dot org > http://www.coggeshall.org/ > -~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~- > > > >-----Original Message----- > >From: Thomas [mailto:zaxisnet@hotmail.com] > >Sent: Wednesday, April 02, 2003 9:27 PM > >To: php-general@lists.php.net > >Subject: [PHP] Submit Image Button > > > > > >I have a problem with my php. > > > >I have a form and in that form there is an image submit > >button. When I click on it, it won't tell me if the submit > >button is clicked. It works fine with a normal one. > > > >sample: > > > ><? > > if (!$submit) { > >?> > > > > <form name="" method="post" action="<?php echo $PHP_SELF > > ?> > > <input type="text" name="username" size="20" > > Class="Box"> > > <input type="password" name="passwd" size="20" > > Class="Box> > > <input type="checkbox" name="remember" > > value="1"> > > <input type="image" > >src="../News/themes/xFClan/button_submit.gif" > >border="0" name="submit" value="Login" width="55" > >height="19" > >alt="Submit"> > > </form> > > > ><? > > } else { > > echo "you clicked"; > > } > >?> > > > >If I use <input type="submit" ... > This works fine....do I > >need to do something else with the code? Help is very appreciated. > > > >Cheers. > > > > > > > > > >-- > >PHP General Mailing List (http://www.php.net/) > >To unsubscribe, visit: http://www.php.net/unsub.php > > > > >