Re: mysql_num_rows
| From: | Mike Tuller | Date: | Fri, 04 Apr 2003 22:49:51 +0000 |
| Subject: | Re: mysql_num_rows | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-142452@lists.php.net to get a copy of this message | ||
I can't believe I forgot that. time to go home for the week.
thanks.
On Friday, April 4, 2003, at 04:28 PM, J J wrote:
oh and your SQL statement is wrong: SELECT * FROM table WHERE ---- you are missing the FROM... --- Mike Tuller <php@ce.anoka.k12.mn.us> wrote:I can't get mysql_num_rows to work for some reason. Here is a snippet of what I have $department_name = $_POST['department_name']; $select_query = "SELECT * WHERE department_name = '$department_name'"; $select_result = mysql_query($select_query, $db_connect); $select_total_rows = mysql_num_rows($select_result); if ($select_total_rows<1) { $insert_query = " insert into departments (department_name) values ('$department_name')"; mysql_query($insert_query, $db_connect) or die (mysql_error()); I am getting back an error mysql_num_rows(): supplied argument is not a valid MySQL result resource. I have looked over it again and again, and can't see what is wrong. Can anyone else see where the problem might be? Mike -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php__________________________________________________ Do you Yahoo!? Yahoo! Tax Center - File online, calculators, forms, and more http://tax.yahoo.com