RE: [PHP] PHP/MySql Help
| From: | Jennifer Goodie | Date: | Wed, 09 Apr 2003 21:22:01 +0000 |
| Subject: | RE: [PHP] PHP/MySql Help | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-143211@lists.php.net to get a copy of this message | ||
It looks okay, what error are you getting? Without an error your problem is
hard to diagnose. You do realize that you are selecting and not inserting,
right? It seems obvious, but you did not give any errors and the only thing
that is really sticking out to me is your result identifier for a select is
called $insert.
> -----Original Message-----
> From: UGADawgs6910@aol.com [mailto:UGADawgs6910@aol.com]
> Sent: Wednesday, April 09, 2003 1:38 PM
> To: php-general@lists.php.net
> Subject: [PHP] PHP/MySql Help
>
>
> Do you know why the following code wouldn't work?
>
> mysql_connect ("localhost", "crosse5_stringdo", "******") or die
> ('I cannot
> connect to the database because: ' . mysql_error());
> mysql_select_db ("crosse5_stringdoctororders");
>
>
> $insert = MYSQL_QUERY("SELECT ordernumber, name, emailaddy,
> dateupdate, timeupdate, stickstatus, received, predicted, express, mail,
> headnum, pocket, notes, payment FROM tracker where
> ordernumber='$OrderNumber'");
> ?>
>
> I have no idea, please help!
>
> Daniel Wood
> Stringdoctor.com
>