RE: [PHP] preg_replace flaw

Is there some way to relate 8000 or 8001 to the image name you want to replace? Or do you just want the first pattern matched to be replaced with $array[0], the next with $array[1], etc... ? ---John W. Holmes... PHP Architect - A monthly magazine for PHP Professionals. Get your copy today. http://www.phparch.com/ > -----Original Message----- > From: Dan Rossi [mailto:daniel@electroteque.org] > Sent: Thursday, April 10, 2003 6:34 AM > To: Php-General > Subject: [PHP] preg_replace flaw > > hi guys > > i have an issue > > say i have content with > > $content = "[f8000f] [f8001f]"; > > i need to replace the keys within the brackets with images for instance > > $disp = array (8000=>"replace one",8001=>"replace two"); > > currently the code i intergated from a current function at work does this > > foreach ($disp as $key=>$value) { > $replaced = eregi_replace("\[f$key\f\]","$value",$content); > } > > although on the second loop it'll obviously replace the first loop so will > only replace one of them. > > theroetically i need to do this so i can do the replace global for the > entire content > > $find = array ("\[f8000\f\]","\[f8001\f\]"); > $replace = array("replace one","replace two"); > > $replaced = ereg_replace($find,$replace,$content); > > but doesnt seem to work any ideas ? > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php