Re: Imagecopyresampled()

Liam Gibbs wrote:

... imagecopyresampled($destinationimage, "$LogoDirectory/$sourceimage", 0, 0, 0, 0, $logothumbnailwidth, $logothumbnailheight, $logopicwidth, $logopicheight); I get Warning: imagecopyresampled(): supplied argument is not a valid Image resource

Second parameter (i.e. source image) of imagecopyresampled() should be resource, not string. Create source image with imagecreatefromjpeg() and use it in imagecopyresampled().

... Same results. Finally, I just try simply this: $destinationimage = imagecreatefromjpeg($_FILES["logotoupload"]["tmp_name"]); and get this: Fatal error: Call to undefined function: imagecreatefromjpeg()

Just a hint from PHP manual (maybe that helps a little): "In order to read and write images in jpeg format, you will need to obtain and install jpeg-6b (available at ftp://ftp.uu.net/graphics/jpeg/), and then recompile gd to make use of jpeg-6b. You will also have to compile PHP with --with-jpeg-dir=/path/to/jpeg-6b." -- Pavel a.k.a. Papi