Re: Image script
| From: | Lowell Allen | Date: | Sun, 13 Apr 2003 13:32:10 +0000 |
| Subject: | Re: Image script | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-143662@lists.php.net to get a copy of this message | ||
> From: "luther" <lblanton@spacebetween.com>
>
> Is there a script to use with images that will determine which graphic is
> needed by the name of the page? For example, say you have a site which uses
> a unique header graphic for each section but you don't want to hardcode the
> exact name of the image into each HTML page. So, if you have a file called
> "news.php" it would automatically determine the "News" graphic is needed
> for
> that page.
>
> Any help would be appreciated as I've looked and looked and can't find a
> script like this anywhere.
You can write simple functions that display specific sections of a page
(using different graphics or menus or whatever) based on URL:
function display_header($page) {
if (ereg("page_name_1", $page) {
$graphic = "this.jpg";
} elseif (ereg("page_name_2", $page){
$graphic = "that.jpg";
} else {
$graphic = "default.jpg";
}
// HTML code using $graphic
}
When you call the function, pass it the value of the current page:
display_header($PHP_SELF);
--
Lowell Allen