Re: Create array from directory

In article <1050306987.2215.35.camel@pb004.pbpc.co.za>, cblake@pbpc.co.za says... > Howdy Mr. Allen, > > First off, thanks for the assistance...I found a similar example at > php.net after looking up is_file(), however, my problem is still there. > > Running the code below just turns up an empty page : > ----------------------------------------------------------- > <?php > > $image_dir = '../graphics/'; > $dir = opendir($image_dir); > $gallery = array(); > > while ($file = readdir($dir)) > { > $filepath = $image_dir . $file ; > if (($file !='.' && $file !='..') && > is_file($filepath)) > { > array_push($gallery, [$file]); > } > } > closedir($dir); > sort($gallery); > srand ((float)microtime()*1000000); > shuffle ($gallery); > ?> > <html> > <head> > <title>Shuffling Arrays</title> > </head> > <body> > <center> > <H1>Shuffling Arrays</H1> > <table width="100%"> > <tr> > <?php > for ($i = 0; $i < 3; $i++) > { > print '<td align = "center"><img src = "'; > print ($filepath); > print '" width = "100" height = > "100"></img></td>'; > } > > print $filepath; > ?> > </tr> > </table> > </center> > </body> > </html> > ----------------------------------------------------------------- > The intention behind this is to open a dir, place all the images into > the array and then randomly select 3 images for display on the page. > > I`ve tried a few things now but still a blank page ! > > Any ideas ? That code appears to create an array $gallery of filenames - however you don't appear to use that array when you are trying to display; the following code may work as you expect <H1>Shuffling Arrays</H1> <table width="100%"> <tr> <?php for ($I = 0; $I < 3; $I++) { echo '<td align = "center"><img src = "'; echo $gallery{$I}; echo '" width = "100" height = "100"></img></td>'; } // print $filepath; ?> </tr> </table> -- Quod subigo farinam $email =~ s/oz$/au/o;