Re: Will $_GET throw an error? (no problem just doubt)

Depending on how you have your error levels set, you will get a WARNING that $_GET[???] does not exist. A better way would be to use something like: $key = (exists($_GET['key'])?$_GET['key']:'someDefaultValueMeaningfulToYou'; This way you will not get a warning and $key will always have a meaningful value. HTH, =C= * Cal Evans * http://www.christianperformer.com * Stay plugged into your audience ----- Original Message ----- From: "Ryan A" <ryan@jumac.com> To: <php-general@lists.php.net> Sent: Saturday, May 03, 2003 10:41 AM Subject: [PHP] Will $_GET throw an error? (no problem just doubt) > Hi, > I am converting my script to work if register globals are off...I have a > simple question > > I have some variables that may or may not be sent from the server namely > $key (and) > $hash > if one is sent the other wont be...so my question is if i declare both like > so: > $key = $_GET['key']; > $hash = $_GET['hash']; > but what happens when only one is sent and not the other? will i get an > error/warning or.....? > > kindly reply. > > Cheers, > -Ryan > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >