Re: Getting result from URL

No, I'm sending them using the GET method. Thank you so much! This script might end up being published so what should I do incase a server is not running 4.3.0? Thanks, Stephen Craton http://www.melchior.us ----- Original Message ----- From: "John Coggeshall" <john@coggeshall.org> To: "Stephen" <webmaster@melchior.us> Cc: "PHP List" <php-general@lists.php.net> Sent: Monday, May 12, 2003 6:29 PM Subject: Re: [PHP] Getting result from URL On Mon, 2003-05-12 at 19:22, Stephen wrote: > I have a URL that if you send it parameters, it gives back a result in plain text. What I want to do is dynamically send the parameters to the URL, get the result back, and display certain information on the result. You mean like a web service type of thing? > My question is.. How would I get the result from the URL after sending it the parameters? If all you need to do is capture the data sent from a HTTP request, from PHP 4.3.0 and up you can use streams with anything using a file reference (like fopen, fread, fgets, etc)... hence: $doc = ""; $fr = fopen("http://www.coggeshall.org/index.php?foo=1&bar=2", 'r'); while(!feof($fr)) { $doc .= fread($fr, 1024); } fclose($fr); If you need to pass parameters to the remote script via the POST method, things are a bit more complex -- but that's basically the idea. John -- -~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~- John Coggeshall john at coggeshall dot org http://www.coggeshall.org/ -~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~--~=~- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php