Re: wierd if statement problem

sorry forget those examples groupID should be either 1 or 2 and not 3, check the other examples i've sent if they work i'm stumped :\ > On Wednesday 21 May 2003 14:06, daniel@electroteque.org wrote: >> this is wierd i have not experienced this before , but i am doing >> groupId checking for my authentication system , say i'm logged is as >> admin , but also need to check for super user access >> >> if (($_SESSION['groupID']!==1) || ($_SESSION['groupID']!==2)) i've >> done this before but for some reason its not working now ?? > > The above statement looks perfectly OK. > > - What does $_SESSION['groupID'] contain? > - What did you expect to happen? > - What actually happened? > > My guess is that you want a logical AND rather than OR. > > -- > Jason Wong -> Gremlins Associates -> www.gremlins.biz > Open Source Software Systems Integrators > * Web Design & Hosting * Internet & Intranet Applications Development * > ------------------------------------------ > Search the list archives before you post > http://marc.theaimsgroup.com/?l=php-general > ------------------------------------------ > /* > The verdict of a jury is the a priori opinion of that juror who smokes > the worst cigars. > -- H. L. Mencken > */ > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php