Re: This line does not execute...
| From: | Alex Ciurea | Date: | Tue, 03 Jun 2003 15:39:42 +0000 |
| Subject: | Re: This line does not execute... | ||
| References: | 1 2 3 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-149988@lists.php.net to get a copy of this message | ||
Ok Tod, this is what I understood so far:
1) image.php should generate for you a barcode;
2) you placed an echo statement inside image.php and nothing happens
Marek have good ideea: try to see the html source code, the code that is
interpreted by your browser.
the executable file ./image.php probably don't run.
try to see, from your shell (i think you use linux) if u can run a php
script. e.g.: ./myscript.php
----- Original Message -----
From: "Todd Cary" <todd@aristesoftware.com>
To: "Alex Ciurea" <alex@netonwave.com>
Cc: "php mailing" <php-general@lists.php.net>
Sent: Tuesday, June 03, 2003 6:22 PM
Subject: Re: [PHP] This line does not execute...
> Alex -
>
> The code I placed in the messsage is a copy and paste of the code from
> the sample.php script provided by the author of the barcode class and it
> agrees with the demo he has on his site.
>
> The "error" is that nothing is happening which I interpret as the file,
> image.php is not being accessed (I put an Echo statement inside it and
> it does not execute). Here is the complete block of code:
>
> if ($obj) {
>
> if ($obj->DrawObject($xres)) {
> echo "<table align='center'><tr><td><img
> src='./image.php?code=" . $barcode . "&style=" . $style .
> "&type=" .
> $type . "&width=" . $width . "&height=" . $height .
> "&xres=" . $xres .
> "&font=" . $font . "'></td></tr></table>";
>
> // My debug code - this line executes!
> echo "<table align='center'><tr><td><font
> color='#FF0000'>Success: Barcode = " . $barcode .
> "</font></td></tr></table>";
> } else {
> echo "<table align='center'><tr><td><font
> color='#FF0000'>" .
> ($obj->GetError()) . "</font></td></tr></table>";
>
> // My debug code
> echo "<table align='center'><tr><td><font
> color='#FF0000'>Problem; Barcode = " . $barcode .
> "</font></td></tr></table>";
> }
> } else {
> // My debug code
> echo "<table align='center'><tr><td><font
> color='#FF0000'>Obj is
> false; Barcode = " . $barcode .
> "</font></td></tr></table>";
> }
>
>
> Alex Ciurea wrote:
>
> >did u made copy&paste with your code?
> >
> >yes? then why don't you try to use the path='image.php?blahblahmoreblah'
> >????
> >
> >no? then please give us more details about the error you're getting...
> >
> >good luck,
> >Alex
> >
> >
> >----- Original Message -----
> >From: "Todd Cary" <todd@aristesoftware.com>
> >To: <php-general@lists.php.net>
> >Sent: Tuesday, June 03, 2003 6:03 PM
> >Subject: [PHP] This line does not execute...
> >
> >
> >
> >
> >>I am trying to get the Sample Barcode to run on my server, however the
> >>following line does not execute:
> >>
> >> echo "<table align='center'><tr><td><img
> >> src='./image.php?code=" .
> >>$barcode . "&style=" . $style . "&type=" . $type .
> >>"&width=" . $width .
> >>"&height=" . $height . "&xres=" . $xres .
> >>"&font=" . $font .
> >>"'></td></tr></table>";
> >>
> >>To see if it is executing, I have an "Echo" statement in the script.
> >>
> >>The image.php file is in the same directory as the other script files.
> >> What am I missing here?
> >>
> >>Todd
> >>--
> >>
> >>
> >>
> >
> >.
> >
> >
> >
>
> --
>
>