RE: [PHP] please help, simple problem (i think)
| From: | John W. Holmes | Date: | Sat, 07 Jun 2003 22:13:19 +0000 |
| Subject: | RE: [PHP] please help, simple problem (i think) | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-150612@lists.php.net to get a copy of this message | ||
> Feeling a little braindead, please help.
You post here more than I do.
> The below program as you can see is extremly simple,
> it connects to the database and runs a select (COUNT) query, this
query
> will
> return 5 rows...so far so good, everything is working but I have no
idea
> how
> to assign each of the rows to a variable so I can use it...
> something like:
> $one=$row[1];
> $two=$row[2];
> $thr=$row[3];
>
> heres the code:
>
> <?php
> require "configbwh.php";
>
> $connected=mysql_connect ("$hostt", "$userr", "$passs") or die
> ('I
cannot
> connect to the database because: ' . mysql_error());
> mysql_select_db ("$db");
>
> $tt = "SELECT ptype, count(*) FROM mylist WHERE ptype IN ('1', '2',
'3',
> '4','5') GROUP BY ptype";
>
> if($res= mysql_query($tt))
> {
> while($row = mysql_fetch_row($res))
> {
> print($row[1]);
$var[$row[0]] = $row[1];
Now $var is an array such as
$var[type 1] = count 1
$var[type 2] = count 2
To cycle through and display it:
foreach($var as $key => $value)
{ echo "$key : $value"; }
---John W. Holmes...
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