Re: Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in f:\.....\none.php on line 286

From: Date: Mon, 09 Jun 2003 21:59:10 +0000
Subject: Re: Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in f:\.....\none.php on line 286
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Hi Philip and Thomas and All. Thanks very much for yours helps. I am Brazillian and I speak in portuguese, for this, I am sorry very much for my bad english. After a long time, my code works very good! But, I dont understand what was the problem! My code was: $result = sql_query("select categoria, nombre, datafim from ".$prefix."_anuncios order by datafim limit 0,30", $dbi); while (list($categoria, $nombre) = sql_fetch_row($result, $dbi)) { $content .= "<img src=blocks/images/diamond.gif>&nbsp;<a href=\"modules.php?name=Concurso\"><font color=\"#096C88\"><b>$categoria </b> $nombre</a>&nbsp;"; } and dont works. If I change it for: //$result = sql_query("select categoria, nombre, datafim from ".$prefix."_anuncios order by datafim limit 0,30", $dbi); $sql = "select categoria, nombre, datafim from ".$prefix."_anuncios order by datafim limit 0,30"; while (list($categoria, $nombre) = sql_fetch_row($result, $dbi)) { $content .= "<img src=blocks/images/diamond.gif>&nbsp;<a href=\"modules.php?name=Concurso\"><font color=\"#096C88\"><b>$categoria </b> $nombre</a>&nbsp;"; } It works very good! My question: In while instruction have a $result and $dbi. They dont are necessary in the sql_query? Understand me? Marcelo --- Outgoing mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.488 / Virus Database: 287 - Release Date: 5/6/2003

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