Re: Pipe $var to a shell command

From: Date: Fri, 13 Jun 2003 22:48:30 +0000
Subject: Re: Pipe $var to a shell command
References: 1  Groups: php.general 
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Oh, sorry, I missunderstood you... You want $myoutput to be the programs input, not the output of the program... Hmm... Look into popen(), fputs() and fclose()... "Tim T" <tim@bwsweb.net> skrev i meddelandet news:20030613215805.43303.qmail@pb1.pair.com... > I have a mem var $myoutput I would like to pipe it to the input of a > shell_exec command. > > I tried shell_exec("command < $myoutput") however this is not quite right. > Anybody have any ideas?? > >

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