How to insert a variable into a PHP template.

From: Date: Mon, 07 Jul 2003 12:34:46 +0000
Subject: How to insert a variable into a PHP template.
Groups: php.general 
Request: Send a blank email to php-general+get-154174@lists.php.net to get a copy of this message
Hi, I want to write a PHP template with a variable number of the last recordset in a MySQL DB being the number referenced in the file. This is so my file can be saved as a PHP page looking at the right content in a database for a content management system. I am stuck on the way to do it. The code below is the part I want to change: So I need to do two things: 1) Select the last record in a database table. 2) get PHP to write all the code below on the fly. //////////////////////// db_connect(); // This is the query number which needs to be changed and written every time as the last record in the DB $query = "select * from crm_content where PageID='1'"; $result = mysql_query($query) or die("Error: Query failure with<BR>$query<BR>".mysql_error()); while ($array = mysql_fetch_array($result)) { $PageTitle = "{$array["Title"]}"; $BodyText = "{$array["BodyText"]}"; $Picture1 = "{$array["PictureOne"]}"; $Picture2 = "{$array["PictureTwo"]}"; $CatID = "{$array["CatID"]}"; } // then write the function to call the page here ////////////////////// Any ideas thoughts or help much appreciated. Steve Jackson Web Development and Marketing Manager Viola Systems Ltd. http://www.violasystems.com stephen.jackson@violasystems.com Mobile +358 50 343 5159

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