Re: isset function problem

... or: if(!empty($SenderEmailAddress)) { ... } Dean E. Weimer wrote: > What about the rest of the code? How is this variable defined? I > have had this happen in some code before, I found that the variable > was set to "". Try using: > > if (isset($SenderEmailAddress) && $SenderEmailAddress != "") { > mail($mailTo, $mailSubject, $Message); > } > >> I have the following code : >> >> Quote: >> >> if (isset($SenderEmailAddress)){ >> mail($mailTo, $mailSubject, $Message); >> } >> >> Unquote >> >> All I want to do is that , if the $SenderEmailAddress is not >> entered, the mail() function should not run. However, >> if the $senderEmailAddress variable is not set, the error I get is >> "No recipient addresses found in header " >> >> Can someone help and tell me why I get this error? >> >> Thanks >> Denis >> >> >> >> -- >> PHP General Mailing List (http://www.php.net/) >> To unsubscribe, visit: http://www.php.net/unsub.php