Re: Re: Eval var from query
| From: | Kevin Stone | Date: | Mon, 14 Jul 2003 19:23:25 +0000 |
| Subject: | Re: Re: Eval var from query | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-155150@lists.php.net to get a copy of this message | ||
The string you send to eval() must be valid PHP code. So try this..
eval( 'echo "'.$data.'";');
- Kevin
----- Original Message -----
From: "Shawn McKenzie" <nospam@mckenzies.net>
To: <php-general@lists.php.net>
Sent: Monday, July 14, 2003 1:15 PM
Subject: [PHP] Re: Eval var from query
> eval($data)
>
> returns Parse error: parse error, unexpected T_STRING in
> C:\apps\apache2\htdocs\test\query.php(23) : eval()'d code on line 1
>
> Thanks!
> Shawn
>
> "Shawn McKenzie" <nospam@mckenzies.net> wrote in message
> news:20030714190325.34064.qmail@pb1.pair.com...
> > How can I evaluate a var that is from a text field of a database?
> Example:
> >
> > MySQL field
name = hi my name is $name
> >
> > In my script I have:
> >
> > $name = "Shawn";
> >
> > After fetching a query result as an associative array I have the
contents
> of
> > the name field in $data
> >
> > If I echo $data I get: hi my name is $name
> >
> > I would like to get: hi my name is Shawn
> >
> > TIA,
> > Shawn
> >
> >
>
>
>
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