And I still don't see how your proposed method handles the problem you mentioned above with Image2...
RDB
Now, first, what would you prefer? Second, I hope you understand how the new
feature would address the issue (and that you know what the issue is - if i explained it clearly, of course)
As sent to www-talk@w3c.org (please read in total, some stuff added)
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consider:
Image1 : 100x100 (Ratio = 1:1)
Image2 : 100x200 (Ratio = 1:2)
Space available for display : 75x75
now, i can say "width=75% height=75%", but this will
only work for Image1, since Image2 will end up
as 75x150 (which clearly does not fit the 75x75 constraints)
now, if i specify "width=75 height=75",
again, this works for Image1, but
not Image2, since the new Image2 ratio will be 1:1,
with Image2 losing 1/2 of it's heigth ratio.
Rather, with "img width=75 height=75 ratio=keep", we will have the following results:
Final Display:
Image1 : 75x75 : (RATIO 1x1)
Image2 : 38x75 (37.5x75) : (RATIO 1:2)
This is something simple enough for the browser to handle, and I think it should.
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Now, as far as not seeing how this helps, keep in mind that this is NOT a feature, but
SHOULD, and a reponse I got from www-talk@w3c.org is the following:
=========================================================
this is what I use to maintain aspect ratio and constrain the image to the limits I have
if($image_path == "")
{
$relative_directory = "/images/logo.gif";
$size = @GetImageSize(getenv("DOCUMENT_ROOT").$relative_directory);
}
else
{
$relative_directory = "/images/gallery/$sportid/";
$size = @GetImageSize(getenv("DOCUMENT_ROOT").$relative_directory."/".$image_path);
}
$width = $size[0];
$height = $size[1];
if($width > 500)
{
if(($width > 500)&&($height > 400))
{
$width2 = ($size[0] - ( $size[0] * (1 - (500/$size[0]))));
$height2 = ($size[1] - ( $size[1] * (1 - (400/$size[1]))));
}
else
{
$width2 = ($size[0] - ( $size[0] * (1 - (500/$size[0]))));
$height2 = $size[1];
}
}
else
{
$width2 = $size[0];
$height2 = $size[1];
}
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