RE: [PHP] $SCRIPT_FILENAME

I have all my script files in a certain directory structure. I also have a file I include in all my scripts (actually by using the prepend option in php.ini) where I assign these paths to variables like this: $all_sql_files = "/home/php_scripts/sql/"; $all_user_files = "/home/php_scripts/users/"; etc. ... When I need to reference a certain file in a script, I can use the variables to build the path for it. Also this way I can move the script directory around without having to ever change any scripts, just the file containing the paths. I am not aware that PHP gives you the option to search for a file in your directories and return its path other then to used a shell command and parse it's output. On Unix that could be: cd / find . -name filename.extension -print The first line takes you to the top of the directory tree. HTH Marc > -----Original Message----- > From: Bård Farstad [SMTP:bf@ez.no] > Sent: Thursday, September 07, 2000 2:44 PM > To: php-general@lists.php.net > Subject: [PHP] $SCRIPT_FILENAME > > Hi all, > > I want to get the full path of a script which I have included. I use this > in > a class and would like for it to know it's full path. > > is this possible? > > eg: > > file1.php > <? > include( "/some/path/file2.php"); > ?> > > file2.php > <? > print( "file2.php is located at: " . $MY_FULL_PATH ); > ?> > > --bård > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >