You're trying to assign to a function, seriousley messed up. I reccomend you make sure you know PHP before going any >further.
Leif,
Let's try and be a little more constructive.....
Jason,
mysql_query is a function, so you need to "call" it, not "assign to it". For example.....
(is this a little of Java crap mixed in here? VB?)
mysql_query("Select * from mytable");
so, change your code to the following (making a variable $query)...
$query = "Select ";
Now, I'm not sure where you are getting the mysql_fetch_array($sql_uc, MYSQL_ASSOC) from, but there are a few problems here.
First, it;s most likely that you dont have a result-set to fetch an array from. Also, you forgot the trailing ")" in the while statement.
while ($result = mysql_fetch_array($sql_uc, MYSQL_ASSOC) )
{
$query .= " {$result['field_name']} as {$result['display']} ";
}
$query .= " from $season";
mysql_query($query);
I suggest you do a google search for "php mysql_query"
Leif K-Brooks wrote:
Jason Martyn wrote:
Here's kinda what I'm trying to do (not working of course).
[snip unimportant code]
mysql_query = ("select");
while ($result = mysql_fetch_array($sql_uc, MYSQL_ASSOC)
{
mysql_query .= (" ". $season .".".$result['field_name']." as ".$result['display'].",";
}
mysql_query .= ("from ".$season.";");
You're trying to assign to a function, seriousley messed up. I reccomend you make sure you know PHP before going any further.