Re: bug in code - can't find it!

<INPUT TYPE="checkbox" NAME="<? echo $search_result2['user_cd'];?>" VALUE="<?if ($search_result2[a.retired_flag] == 1){?>CHECKED<?}?>"> <?echo $search_result2[a.retired_flag]?> } well for starters checkboxes dont have a size and maxlength you may want to try that and see if it works... ----- Original Message ----- From: "Amanda McComb" <amccomb@indiana.edu> To: <php-general@lists.php.net> Sent: Wednesday, August 06, 2003 2:47 PM Subject: [PHP] bug in code - can't find it! > Ok, after all of the discussion on posting, I'm afraid to post. > Unfortunately, no one I know is a programmer, and I am a beginner. I can > normally figure out what I've done wrong, but I'm missing something here. > > Ok, here is my query and the bit of code I can't figure out: > > $query = "SELECT * from apt_user_t a, apt_company_t b "; > $query .= "WHERE a.user_cd = b.user_cd "; > $query .= "ORDER BY a.username"; > > $search_results = mysql_query($query) or die("Select > Failed!"); > while ($search_result2 = mysql_fetch_array($search_results)) > { > <INPUT > TYPE="checkbox" > NAME="<? echo $search_result2['user_cd'];?>" > SIZE="20" > MAXLENGTH="50" > VALUE="<?if ($search_result2[a.retired_flag] == 1){?>CHECKED<?}?>"> > <?echo $search_result2[a.retired_flag]?> > } > Nothing shows up with the echo or the value. I only included this > checkbox, but all of the other values show up fine. Can someone give me a > hint? > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >