Re: call function as variable

I got this error: Parse error: parse error, unexpected '{' in ....... Cheers John W. Holmes wrote:

adam wrote:

Hi! I have folowing function which they are a member in a class. function foo(){ something } function zoo(){ something else } and i have a array such: $test = array(1=>foo,2=zoo); and i want to call the fuction foo() and zoo something like; $object->$test[1]();

Try: {$object->$test[1]}();