Re: Problem with include();

* Thus wrote Ty Lamb (Subscriptions@AarynAndTy.com): > /index.php > has > include("/code/includes/page_header.php"); > > /docs/aaryn/dmb/dave.php > has > include("/code/includes/page_header.php"); > > Both are identical lines of code. Index.php works but dave.php returns the > following: > > Warning: Failed opening '/code/includes/page_header.php' for inclusion > (include_path='.;c:\php4\pear') in C:\x\x\x\x\x\aaryn\dmb\dave.php on line 4 > > but if I change the code in dave.php to > include '../../../code/includes/page_header.php'; ahh.. so your code/ is at your webroot (the same directory as index.php?) I would have expected the /code to look at c:\code\includes\page_header.php But it seems that this isn't the case and I'm not familiar with how windows handles the absolute path. > > It works. > > Why? > > Is there any way around this? Please tell me I'm doing something wrong and > it's not supposed to work like this!!! What I would suggest is to setup your include_path to look something like: include_path=".;c:\php4\pear;c:\path\to\code\includes" Then your include will simply be include("page_header.php"); Curt -- "I used to think I was indecisive, but now I'm not so sure."