Re: More Image Transformation Difficulty

Anytime you encounter any error with images, comment out Content-Type header and you will see the error right in your browser. In this case the error is <b>Fatal error</b>: Call to undefined function: imagejpg() in <b>/usr/home/jakus1/www/htdocs/jpg.php</b> on line <b>64</b> should be imagejpeg weston@leary.csoft.net wrote:

I'm trying to write a script that pulls an image from a database and transforms the size if passed a width via the url query string. Thanks to the helpful hint about the function "imagecreatefromstring", I think I'm now able to ready image data I've pulled for a database with GD. However, I'm still having trouble resizing... at least, when I'm sending the image to my browser, I'm being told that it "cannot be displayed, because it contains errors." (And the script does work if I don't try resizing... see below for example URL). Here's what I'm doing: $row = mysql_fetch_row($dbresult); $imgdata = $row[0]; if(isset($width) && !empty($width) && is_numeric($width)) /* only do transformation if given a width */ { $gdimg = imagecreatefromstring($imgdata); $srcWidth = imagesx($gdimg); $srcHeight = imagesy($gdimg); $scaleFactor = $width/$srcWidth; $targetHeight = $srcHeight * $scaleFactor; $resizedimg = imagecreatetruecolor($width,$targetHeight); imagecopyresized($resizedimg,$gdimg,0,0,0,0,$width,$targetHeight,$srcWidth,$srcHeight); } header("Content-Type: image/jpeg"); header("Content-Transfer-Encoding: binary\n"); //send file contents if(!empty($resizedimg)) imagejpg($resizedimg); else { header("Content-length: " . strlen($imgdata) . "\n"); print($imgdata); } Does anyone see what I'm doing wrong? Again, the script actually works if I don't try to do the transform. See: http://www.fsboutah.net/jpg.php?table=homes&key=4&field=Picture1 and http://www.fsboutah.net/jpg.php?table=homes&key=4&field=Picture1&width=100 for contrasts. -W