RE: [PHP] Date calculations

From: Date: Tue, 12 Sep 2000 08:13:42 +0000
Subject: RE: [PHP] Date calculations
Groups: php.general 
Request: Send a blank email to php-general+get-16283@lists.php.net to get a copy of this message
> What I am trying to do is take the current date then try to > get the date from four days back. For instance, today is the > 12th September, I want the system to look at this, subtract > four days off, and get the 8th September in the format > 2000-09-08 [date ("y-m-d)]. $currentdate = Date("U"); // Unix timestamp, seconds since 1970. $minute = 60; // Seconds in a minute $hour = 60*$minute; // Minutes in an hour $day = 24*$hour; // Hours in a day $dayfour = 4*$day; // Days in 4 days (duh) $datefourdaysago = $currentdate - $dayfour; // Unix timestamp 4 days ago. $dateoutput = date("Y-m-D", $datefoursaysago); Have fun :) Jason

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