Re: Re: regexp: 'a correctly parenthesized substring advanced'

hi marek, thanx for your suggestion. i have tried out the tokenizer but 1. i think its not realy final and can change in the future 2. the tokenizer can only find real php code but i need to find my simplified php code without an ; on the end of an statement for example. so the tokenizer doesn't do my job. i'm not far from the right solution it's a litle step to bring the regex working with embeded parenthesis beetween " " i only had 2pregs in the complete source that can catch any type of registered function call with the simplified syntax ... this is fast enough for me ... "Marek Kilimajer" <kilimajer@webglobe.sk> schrieb im Newsbeitrag news:3F796BFD.1070108@webglobe.sk... > Forget regexp and try this function: > http://sk.php.net/manual/en/function.token-get-all.php > > Jaaboo wrote: > > > I give an wrong example. Here is a better one > > > > <?php > > > > $txt = "func1($par1," 100 (euro)", func2($par2,"(c) by > > nobody"))"; > > > > if (preg_match_all(' > > > > / > > > > ([a-zA-Z]\w*?) > > > > \s* > > > > ( > > > > \( > > > > ( > > > > (?>.*?)| > > > > .*?(?R)* > > > > ) > > > > \) > > > > )+ > > > > /x > > > > ', $txt, $m)){ > > > > print_r($m); > > > > } else { > > > > echo "no match"; > > > > } > > > > echo "\n"; > > > > > > > > ?> > > > > This must result in : > > > > First call: func1($par1," 100 (euro)", func2($par2,"(c) by nobody")) > > Second call with the inner part $par1," 100 (euro)", func2($par2,"(c) by > > nobody") > > must result in : func2($par2,"(c) by nobody") > > > > > > > > Please visit www.regexp.org there is an open thread of this question. > > > > thanx > >