RE: [PHP] array_diff
| From: | Angelo Zanetti | Date: | Thu, 02 Oct 2003 09:28:23 +0000 |
| Subject: | RE: [PHP] array_diff | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-164712@lists.php.net to get a copy of this message | ||
thanx Eugene,
I know what the problem was, firstly that when doing an array_diff the keys
are preserved. Therefore If I was looping through $arrayResult for the count
of elements (in this case 2) then thats where the blank value comes in. SO
therefore if I wanted to get all the values out of the $arrayResult that are
not blank, would I loop through the array the amount of times that there are
elements in the $array1, because $arrayResult will be the same size as
$array1 and also because the keys are preserved?
Im not sure if Im heading in the right direction, with regards to gettig the
values out the $arrayResult.
TIA.
-----Original Message-----
From: Eugene Lee [mailto:list-php-1@fsck.net]
Sent: Thursday, October 02, 2003 11:09 AM
To: Php-General@Lists.Php.Net
Subject: Re: [PHP] array_diff
On Thu, Oct 02, 2003 at 10:44:15AM +0200, Angelo Zanetti wrote:
:
: I am getting some weird results when using the array_diff() function.
:
: eg: $arrayResult = array_diff($array1, $array2);
:
: When i use it the resulting array ($arrayResult) gets the correct number
of
: elements, however when I echo the elements in $arrayResult it contains
some
: blank values.
:
: eg:
:
: $array1 = [123] [120] [44] [54]
: $array2 = [120] [54]
:
: then when I display $arrayResult:
: [123] ... -> blank value which should be 44.
It works for me:
<?php
$arr1 = array(123, 120, 44, 54);
$arr2 = array(120, 54);
$arr3 = array_diff($arr1, $arr2);
print_r($arr3);
?>
with the output:
Array
(
[0] => 123
[2] => 44
)
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