Re: problem with intval and !=

From:	Greg Beaver	Date:	Thu, 23 Oct 2003 16:28:22 +0000
Subject:	Re: problem with intval and !=
References:	1 2 3 4 5 6 7 8 9	Groups:	php.general
Request:	Send a blank email to php-general+get-167310@lists.php.net to get a copy of this message

Hello all, http://www.php.net/is_numeric is the function you are looking for. No need for fancy regexps. Regards, Greg -- phpDocumentor http://www.phpdoc.org Cesar Cordovez wrote:

Sorry, typo, this is what I meant, !is_integer("12thisisnotanumber") retuns true. but also, is_integer("12") return false. therefore, is_integer(12) return true. So, how can I check if what ever the user writes is an integer or not, knowing that he will write it in a string field. Any how, I solved the problem with preg_match("/^([0-9]+)$/", $value) Thanks for your help, list!!!! =) Robert Cummings wrote:
On Thu, 2003-10-23 at 11:41, Cesar Cordovez wrote:
Because is_integer("12thisisnotanumber") retuns true.
Not for me it doesn't. Returns false. Prolly because it's a string. Even the following returns false for me:
    is_integer("12")
Cheers, Rob.