Re: fopen url

On Friday 07 November 2003 04:12, John Hagstrand wrote: > I'm trying to read a URL. > > this works: fopen( "http://www.google.com") > > this does not work: fopen( "http://news.google.com") As it stands, neither of the above will work. fopen() requires at least 2 parameters. When you post code, please post the *exact* code that you use. > If the URL does not start with "www", then fopen writes and error message > that says "success" and returns false. What's up with that? Did you jump to that conclusion based solely on the two example URLs above? For the record: echo fopen("http://www.google.com", 'r'); echo fopen("http://news.google.com", 'r'); works fine for me. -- Jason Wong -> Gremlins Associates -> www.gremlins.biz Open Source Software Systems Integrators * Web Design & Hosting * Internet & Intranet Applications Development * ------------------------------------------ Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general ------------------------------------------ /* Humans are communications junkies. We just can't get enough. -- Alan Kay */