Re: giving variable value in URL problem

On Sunday 16 November 2003 13:31, Burak Delice wrote: Please do not top-post, it makes replying in a coherent fashion *much* harder. I've corrected it for you. > "Chris Shiflett" <shiflett@php.net> wrote in message > news:20031116013859.72734.qmail@web14307.mail.yahoo.com... > > > --- Burak Delice <bdelice@yahoo.com> wrote: > > > http://localhost/menu.php?status=0 php return > > > > [snip] > > > > > if ($status==0) echo '"trying"; > > > > if (!$_GET['status']) > > { > > echo '"trying"; > > } > thanx Chris, > this code is running on Web, is not on Local. and I did your way, it did > not work Could you explain exactly *how* it didn't work? With the code as it is above you ought to get a parse error. If you've corrected the parse error, did you then try printing out $_GET['status'] to see what it contains? And feed it different values to check that it works or doesn't work for values other than 0 (zero)? -- Jason Wong -> Gremlins Associates -> www.gremlins.biz Open Source Software Systems Integrators * Web Design & Hosting * Internet & Intranet Applications Development * ------------------------------------------ Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general ------------------------------------------ /* I was playing poker the other night... with Tarot cards. I got a full house and 4 people died. -- Steven Wright */