Re: Php ignores if statement

On Sat, 2003-11-22 at 13:57, Pieter wrote: > I recently started coding online and i have the weirdest response, my code is: > > <?php > > include 'function.inc'; > > echo "$id<br>"; > > print (gettype($id)); > > if ($id = "add" ) > > { > > echo "is add"; > > exit; > > } > > > if ($id = "own" ) > > { > > > echo "id is own"; > > exit; > > } > > if ($id = "all" ) > > { > > > echo "id is all"; > > exit; > > } > > ?> > > $id in this case = "own", but it totally ignores this value and uses the first if > statement and treats $id as if it has a value of "add". I am very frustrated and i really > hope someone can help me. The server is linux, and php version 4.1.2 > > Thanks > Don't use = use == By using the = you are assigning $id to that value making the if statement always true. The compare one to the other use == instead -- "I have a photographic memory. I just forgot the film" --Unknown ============================= Ryan Thompson rthomp@sympatico.ca http://osgw.sourceforge.net